((x)/(x+3))-((10)/(x+4))=1

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Solution for ((x)/(x+3))-((10)/(x+4))=1 equation: 


D( x )

x+4 = 0

x+3 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-4) U (-4:-3) U (-3:+oo)

x/(x+3)-(10/(x+4)) = 1 // - 1

x/(x+3)-(10/(x+4))-1 = 0

x/(x+3)-10*(x+4)^-1-1 = 0

x/(x+3)-10/(x+4)-1 = 0

(x*(x+4))/((x+3)*(x+4))+(-10*(x+3))/((x+3)*(x+4))+(-1*(x+3)*(x+4))/((x+3)*(x+4)) = 0

x*(x+4)-10*(x+3)-1*(x+3)*(x+4) = 0

x^2-x^2-6*x-7*x-30-12 = 0

-13*x-42 = 0

(-13*x-42)/((x+3)*(x+4)) = 0

(-13*x-42)/((x+3)*(x+4)) = 0 // * (x+3)*(x+4)

-13*x-42 = 0

-13*x-42 = 0 // + 42

-13*x = 42 // : -13

x = 42/(-13)

x = -42/13

x = -42/13

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