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D( x )
x-3 = 0
x-3 = 0
x-3 = 0
x-3 = 0 // + 3
x = 3
x in (-oo:3) U (3:+oo)
x/(x-3)+5 = 3/(x-3) // - 3/(x-3)
x/(x-3)-(3/(x-3))+5 = 0
x/(x-3)-3*(x-3)^-1+5 = 0
x/(x-3)-3/(x-3)+5 = 0
x/(x-3)-3/(x-3)+(5*(x-3))/(x-3) = 0
5*(x-3)+x-3 = 0
x+5*x-15-3 = 0
6*x-18 = 0
(6*x-18)/(x-3) = 0
(6*x-18)/(x-3) = 0 // * x-3
6*x-18 = 0
6*x-18 = 0 // + 18
6*x = 18 // : 6
x = 18/6
x = 3
x in { 3}
x belongs to the empty set
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