((x+1)/5)-((x-1)/6)=2

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Solution for ((x+1)/5)-((x-1)/6)=2 equation: 



((x+1)/5)-((x-1)/6)=2

We move all terms to the left:

((x+1)/5)-((x-1)/6)-(2)=0

We calculate fractions


(6x+6)/()+(-5x+5)/()-2=0

We multiply all the terms by the denominator


(6x+6)+(-5x+5)-2*()=0

We add all the numbers together, and all the variables

(6x+6)+(-5x+5)=0

We get rid of parentheses

6x-5x+6+5=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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