((x+10)*(2x-3))=(2x)(2x)

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Solution for ((x+10)*(2x-3))=(2x)(2x) equation: 



((x+10)(2x-3))=(2x)(2x)

We move all terms to the left:

((x+10)(2x-3))-((2x)(2x))=0

determiningTheFunctionDomain
((x+10)(2x-3))-2x2x=0

We multiply parentheses ..

((+2x^2-3x+20x-30))-2x2x=0



We calculate terms in parentheses: +((+2x^2-3x+20x-30)), so:

(+2x^2-3x+20x-30)

We get rid of parentheses

2x^2-3x+20x-30

We add all the numbers together, and all the variables

2x^2+17x-30

Back to the equation:

+(2x^2+17x-30)



We get rid of parentheses

2x^2+17x-2x2x-30=0

We move all terms containing x to the left, all other terms to the right

2x^2+17x-2x2x=30

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