((x+13)/(x-2))+1=(15/(x-2))

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Solution for ((x+13)/(x-2))+1=(15/(x-2)) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(x+13)/(x-2)+1 = 15/(x-2) // - 15/(x-2)

(x+13)/(x-2)-(15/(x-2))+1 = 0

(x+13)/(x-2)-15*(x-2)^-1+1 = 0

(x+13)/(x-2)-15/(x-2)+1 = 0

(x+13)/(x-2)-15/(x-2)+(1*(x-2))/(x-2) = 0

1*(x-2)+x-15+13 = 0

x+x-2-2 = 0

2*x-4 = 0

(2*x-4)/(x-2) = 0

(2*x-4)/(x-2) = 0 // * x-2

2*x-4 = 0

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

x in { 2} 

x belongs to the empty set

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