((x+2)+(x+6))/2*x=32

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Solution for ((x+2)+(x+6))/2*x=32 equation: 



((x+2)+(x+6))/2x=32

We move all terms to the left:

((x+2)+(x+6))/2x-(32)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We multiply all the terms by the denominator


((x+2)+(x+6))-32*2x=0



We calculate terms in parentheses: +((x+2)+(x+6)), so:

(x+2)+(x+6)

We get rid of parentheses

x+x+2+6

We add all the numbers together, and all the variables

2x+8

Back to the equation:

+(2x+8)



Wy multiply elements

(2x+8)-64x=0

We get rid of parentheses

2x-64x+8=0

We add all the numbers together, and all the variables

-62x+8=0

We move all terms containing x to the left, all other terms to the right

-62x=-8

x=-8/-62

x=4/31

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