((x+2)/(x+3))-((x-1)/x)-3/40=0

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Solution for ((x+2)/(x+3))-((x-1)/x)-3/40=0 equation: 



((x+2)/(x+3))-((x-1)/x)-3/40=0



Domain of the equation: (x+3))!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(-9x^2-3x)/(120x^2+40x)+(((x+2)*x)*40)/(120x^2+40x)+(-((x-1)*(x+3))*40)/(120x^2+40x)=0



We calculate terms in parentheses: +(((x+2)*x)*40)/(120x^2+40x), so:

((x+2)*x)*40)/(120x^2+40x

We add all the numbers together, and all the variables

40x+((x+2)*x)*40)/(120x^2

We multiply all the terms by the denominator


40x*(120x^2+((x+2)*x)*40)

Back to the equation:

+(40x*(120x^2+((x+2)*x)*40))





We calculate terms in parentheses: +(-((x-1)*(x+3))*40)/(120x^2+40x), so:

-((x-1)*(x+3))*40)/(120x^2+40x

We add all the numbers together, and all the variables

40x-((x-1)*(x+3))*40)/(120x^2

We multiply all the terms by the denominator


40x*(120x^2-((x-1)*(x+3))*40)

Back to the equation:

+(40x*(120x^2-((x-1)*(x+3))*40))



We multiply all the terms by the denominator


(-9x^2-3x)+((40x*(120x^2+((x+2)*x)*40)))*(120x^2+40x)+((40x*(120x^2-((x-1)*(x+3))*40)))*(120x^2+40x)=0



We calculate terms in parentheses: +((40x*(120x^2+((x+2)*x)*40)))*(120x^2+40x), so:

(40x*(120x^2+((x+2)*x)*40)))*(120x^2+40x

We add all the numbers together, and all the variables

40x+(40x*(120x^2+((x+2)*x)*40)))*(120x^2

Back to the equation:

+(40x+(40x*(120x^2+((x+2)*x)*40)))*(120x^2)





We calculate terms in parentheses: +((40x*(120x^2-((x-1)*(x+3))*40)))*(120x^2+40x), so:

(40x*(120x^2-((x-1)*(x+3))*40)))*(120x^2+40x

We add all the numbers together, and all the variables

40x+(40x*(120x^2-((x-1)*(x+3))*40)))*(120x^2

Back to the equation:

+(40x+(40x*(120x^2-((x-1)*(x+3))*40)))*(120x^2)



We get rid of parentheses

-9x^2-3x+(40x+(40x*(120x^2+((x+2)*x)*40)))*120x^2+(40x+(40x*(120x^2-((x-1)*(x+3))*40)))*120x^2=0

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