((x+2)/(x-3))=10

Solution for ((x+2)/(x-3))=10 equation:

((x+2)/(x-3))=10

We move all terms to the left:

((x+2)/(x-3))-(10)=0


Domain of the equation: (x-3))!=0

x∈R


We multiply all the terms by the denominator


((x+2)-10*(x-3))=0


We calculate terms in parentheses: +((x+2)-10*(x-3)), so:

(x+2)-10*(x-3)

We multiply parentheses

(x+2)-10x+30

We get rid of parentheses

x-10x+2+30

We add all the numbers together, and all the variables

-9x+32

Back to the equation:

+(-9x+32)


We get rid of parentheses

-9x+32=0

We move all terms containing x to the left, all other terms to the right

-9x=-32

x=-32/-9

x=3+5/9