((x+2)/(x-3))=6

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Solution for ((x+2)/(x-3))=6 equation: 



((x+2)/(x-3))=6

We move all terms to the left:

((x+2)/(x-3))-(6)=0



Domain of the equation: (x-3))!=0

x∈R



We multiply all the terms by the denominator


((x+2)-6*(x-3))=0



We calculate terms in parentheses: +((x+2)-6*(x-3)), so:

(x+2)-6*(x-3)

We multiply parentheses

(x+2)-6x+18

We get rid of parentheses

x-6x+2+18

We add all the numbers together, and all the variables

-5x+20

Back to the equation:

+(-5x+20)



We get rid of parentheses

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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