((x+2)/2)+((x+1)/3)=7

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Solution for ((x+2)/2)+((x+1)/3)=7 equation: 



((x+2)/2)+((x+1)/3)=7

We move all terms to the left:

((x+2)/2)+((x+1)/3)-(7)=0

We calculate fractions


(3x+6)/()+(2x+2)/()-7=0

We multiply all the terms by the denominator


(3x+6)+(2x+2)-7*()=0

We add all the numbers together, and all the variables

(3x+6)+(2x+2)=0

We get rid of parentheses

3x+2x+6+2=0

We add all the numbers together, and all the variables

5x+8=0

We move all terms containing x to the left, all other terms to the right

5x=-8

x=-8/5

x=-1+3/5

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