((x+2)/3)-((2-x)/6)=x-2

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Solution for ((x+2)/3)-((2-x)/6)=x-2 equation: 


x in (-oo:+oo)

(x+2)/3-((2-x)/6) = x-2 // - x-2

(x+2)/3-((2-x)/6)-x+2 = 0

(x+2)/3+(-1*(2-x))/6-x+2 = 0

(6*(x+2))/(3*6)+(-1*3*(2-x))/(3*6)+(3*6*(-x))/(3*6)+(2*3*6)/(3*6) = 0

6*(x+2)-1*3*(2-x)+3*6*(-x)+2*3*6 = 0

9*x-18*x+6+36 = 0

6-9*x+36 = 0

42-9*x = 0

(42-9*x)/(3*6) = 0

(42-9*x)/(3*6) = 0 // * 3*6

42-9*x = 0

42-9*x = 0 // - 42

-9*x = -42 // : -9

x = -42/(-9)

x = 14/3

x = 14/3

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