((x+2)/4)-((x-1)/3)=2

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Solution for ((x+2)/4)-((x-1)/3)=2 equation: 



((x+2)/4)-((x-1)/3)=2

We move all terms to the left:

((x+2)/4)-((x-1)/3)-(2)=0

We calculate fractions


(3x+6)/()+(-4x+4)/()-2=0

We multiply all the terms by the denominator


(3x+6)+(-4x+4)-2*()=0

We add all the numbers together, and all the variables

(3x+6)+(-4x+4)=0

We get rid of parentheses

3x-4x+6+4=0

We add all the numbers together, and all the variables

-1x+10=0

We move all terms containing x to the left, all other terms to the right

-x=-10

x=-10/-1

x=+10

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