((x+3)-x)/(x+3)(x+3)=0

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Solution for ((x+3)-x)/(x+3)(x+3)=0 equation:



((x+3)-x)/(x+3)(x+3)=0
Domain of the equation: (x+3)(x+3)!=0
We move all terms containing x to the left, all other terms to the right
x+3)(x!=-3
x∈R
We multiply parentheses ..
((x+3)-x)/(+x^2+3x+3x+9)=0
We multiply all the terms by the denominator
((x+3)-x)=0
We calculate terms in parentheses: +((x+3)-x), so:
(x+3)-x
We add all the numbers together, and all the variables
-1x+(x+3)
We get rid of parentheses
-1x+x+3
We add all the numbers together, and all the variables
3
Back to the equation:
+(3)
We move all terms containing x to the left, all other terms to the right
=-3

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