((x+3)/(2x-3))=2

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Solution for ((x+3)/(2x-3))=2 equation: 



((x+3)/(2x-3))=2

We move all terms to the left:

((x+3)/(2x-3))-(2)=0



Domain of the equation: (2x-3))!=0

x∈R



We multiply all the terms by the denominator


((x+3)-2*(2x-3))=0



We calculate terms in parentheses: +((x+3)-2*(2x-3)), so:

(x+3)-2*(2x-3)

We multiply parentheses

(x+3)-4x+6

We get rid of parentheses

x-4x+3+6

We add all the numbers together, and all the variables

-3x+9

Back to the equation:

+(-3x+9)



We get rid of parentheses

-3x+9=0

We move all terms containing x to the left, all other terms to the right

-3x=-9

x=-9/-3

x=+3

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