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D( x )
(4*x+12)/5 = 0
(4*x+12)/5 = 0
(4*x+12)/5 = 0
4*x+12 = 0 // - 12
4*x = -12 // : 4
x = -12/4
x = -3
x in (-oo:-3) U (-3:+oo)
((x+3)/7)/((4*x+12)/5) = 0
(5*(x+3))/(7*(4*x+12)) = 0
x+3 = 0 // - 3
x = -3
x in { -3}
x belongs to the empty set
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