((x+3)/(x-1))-1=(x-5)/(x-4)

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Solution for ((x+3)/(x-1))-1=(x-5)/(x-4) equation:


D( x )

x-4 = 0

x-1 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:4) U (4:+oo)

(x+3)/(x-1)-1 = (x-5)/(x-4) // - (x-5)/(x-4)

(x+3)/(x-1)-((x-5)/(x-4))-1 = 0

(x+3)/(x-1)+(-1*(x-5))/(x-4)-1 = 0

((x+3)*(x-4))/((x-1)*(x-4))+(-1*(x-5)*(x-1))/((x-1)*(x-4))+(-1*(x-1)*(x-4))/((x-1)*(x-4)) = 0

(x+3)*(x-4)-1*(x-5)*(x-1)-1*(x-1)*(x-4) = 0

5*x-x^2+5*x-17-4 = 0

10*x-x^2-21 = 0

10*x-x^2-21 = 0

10*x-x^2-21 = 0

DELTA = 10^2-(-21*(-1)*4)

DELTA = 16

DELTA > 0

x = (16^(1/2)-10)/(-1*2) or x = (-16^(1/2)-10)/(-1*2)

x = 3 or x = 7

(x-3)*(x-7) = 0

((x-3)*(x-7))/((x-1)*(x-4)) = 0

((x-3)*(x-7))/((x-1)*(x-4)) = 0 // * (x-1)*(x-4)

(x-3)*(x-7) = 0

( x-3 )

x-3 = 0 // + 3

x = 3

( x-7 )

x-7 = 0 // + 7

x = 7

x in { 3, 7 }

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