((x+3)/3)-((4x-1)/6)=3+x/3

Solution for ((x+3)/3)-((4x-1)/6)=3+x/3 equation:

((x+3)/3)-((4x-1)/6)=3+x/3

We move all terms to the left:

((x+3)/3)-((4x-1)/6)-(3+x/3)=0

We add all the numbers together, and all the variables

((x+3)/3)-((4x-1)/6)-(x/3+3)=0

We get rid of parentheses

((x+3)/3)-((4x-1)/6)-x/3-3=0

We calculate fractions


(-6x^2)/()+(6x+18)/()+(-((4x-1)*3)*3)/()-3=0


We calculate terms in parentheses: +(-((4x-1)*3)*3)/(), so:

-((4x-1)*3)*3)/(

We multiply all the terms by the denominator


-((4x-1)*3)*3)


We calculate terms in parentheses: -((4x-1)*3)*3), so:

(4x-1)*3)*3

We multiply parentheses

12x+

We add all the numbers together, and all the variables

12x

Back to the equation:

-(12x)


Back to the equation:

+(-12x)


We get rid of parentheses

(-6x^2)/()+(6x+18)/()-12x-3=0

We multiply all the terms by the denominator


(-6x^2)+(6x+18)-12x*()-3*()=0

We add all the numbers together, and all the variables

(-6x^2)+(6x+18)-12x*()=0

We get rid of parentheses

-6x^2+6x-12x*()+18=0

We move all terms containing x to the left, all other terms to the right

-6x^2+6x-12x*()=-18