((x+3)/5)-((2x+1)/4)=2

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Solution for ((x+3)/5)-((2x+1)/4)=2 equation: 


x in (-oo:+oo)

(x+3)/5-((2*x+1)/4) = 2 // - 2

(x+3)/5-((2*x+1)/4)-2 = 0

(x+3)/5+(-1*(2*x+1))/4-2 = 0

(4*(x+3))/(4*5)+(-1*5*(2*x+1))/(4*5)+(-2*4*5)/(4*5) = 0

4*(x+3)-1*5*(2*x+1)-2*4*5 = 0

7-6*x-40 = 0

-6*x-33 = 0

(-6*x-33)/(4*5) = 0

(-6*x-33)/(4*5) = 0 // * 4*5

-6*x-33 = 0

-6*x-33 = 0 // + 33

-6*x = 33 // : -6

x = 33/(-6)

x = -11/2

x = -11/2

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