((x+4)(x+4))=9

Solution for ((x+4)(x+4))=9 equation:

((x+4)(x+4))=9

We move all terms to the left:

((x+4)(x+4))-(9)=0

We multiply parentheses ..

((+x^2+4x+4x+16))-9=0


We calculate terms in parentheses: +((+x^2+4x+4x+16)), so:

(+x^2+4x+4x+16)

We get rid of parentheses

x^2+4x+4x+16

We add all the numbers together, and all the variables

x^2+8x+16

Back to the equation:

+(x^2+8x+16)


We get rid of parentheses

x^2+8x+16-9=0

We add all the numbers together, and all the variables

x^2+8x+7=0

a = 1; b = 8; c = +7;
Δ = b2-4ac
Δ = 82-4·1·7
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-6}{2*1}=\frac{-14}{2}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+6}{2*1}=\frac{-2}{2}
=-1
$