((x+4)/(8-x))=2

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Solution for ((x+4)/(8-x))=2 equation: 



((x+4)/(8-x))=2

We move all terms to the left:

((x+4)/(8-x))-(2)=0



Domain of the equation: (8-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-8

x!=-8/1

x!=-8

x∈R



We add all the numbers together, and all the variables

((x+4)/(-1x+8))-2=0

We multiply all the terms by the denominator


((x+4)-2*(-1x+8))=0



We calculate terms in parentheses: +((x+4)-2*(-1x+8)), so:

(x+4)-2*(-1x+8)

We multiply parentheses

(x+4)+2x-16

We get rid of parentheses

x+2x+4-16

We add all the numbers together, and all the variables

3x-12

Back to the equation:

+(3x-12)



We get rid of parentheses

3x-12=0

We move all terms containing x to the left, all other terms to the right

3x=12

x=12/3

x=4

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