((x+4)/(x+1))+1=(3/(x+1))

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Solution for ((x+4)/(x+1))+1=(3/(x+1)) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(x+4)/(x+1)+1 = 3/(x+1) // - 3/(x+1)

(x+4)/(x+1)-(3/(x+1))+1 = 0

(x+4)/(x+1)-3*(x+1)^-1+1 = 0

(x+4)/(x+1)-3/(x+1)+1 = 0

(x+4)/(x+1)-3/(x+1)+(1*(x+1))/(x+1) = 0

1*(x+1)+x-3+4 = 0

x+x+1+1 = 0

2*x+2 = 0

(2*x+2)/(x+1) = 0

(2*x+2)/(x+1) = 0 // * x+1

2*x+2 = 0

2*x+2 = 0 // - 2

2*x = -2 // : 2

x = -2/2

x = -1

x in { -1} 

x belongs to the empty set

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