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((x+4)/5)+((x+1)/7)=1
We move all terms to the left:
((x+4)/5)+((x+1)/7)-(1)=0
We calculate fractions
(7x+28)/()+(5x+5)/()-1=0
We multiply all the terms by the denominator
(7x+28)+(5x+5)-1*()=0
We add all the numbers together, and all the variables
(7x+28)+(5x+5)=0
We get rid of parentheses
7x+5x+28+5=0
We add all the numbers together, and all the variables
12x+33=0
We move all terms containing x to the left, all other terms to the right
12x=-33
x=-33/12
x=-2+3/4
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