((x+4)/5)-((3x-4)/4)=6

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Solution for ((x+4)/5)-((3x-4)/4)=6 equation:



((x+4)/5)-((3x-4)/4)=6
We move all terms to the left:
((x+4)/5)-((3x-4)/4)-(6)=0
We calculate fractions
(4x+16)/()+(-15x+20)/()-6=0
We multiply all the terms by the denominator
(4x+16)+(-15x+20)-6*()=0
We add all the numbers together, and all the variables
(4x+16)+(-15x+20)=0
We get rid of parentheses
4x-15x+16+20=0
We add all the numbers together, and all the variables
-11x+36=0
We move all terms containing x to the left, all other terms to the right
-11x=-36
x=-36/-11
x=3+3/11

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