((x+4)2)+((x-2)2)=(x+3)+(x+5)+(x+4)

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Solution for ((x+4)2)+((x-2)2)=(x+3)+(x+5)+(x+4) equation: 



((x+4)2)+((x-2)2)=(x+3)+(x+5)+(x+4)

We move all terms to the left:

((x+4)2)+((x-2)2)-((x+3)+(x+5)+(x+4))=0



We calculate terms in parentheses: +((x+4)2), so:

(x+4)2

We multiply parentheses

2x+8

Back to the equation:

+(2x+8)





We calculate terms in parentheses: +((x-2)2), so:

(x-2)2

We multiply parentheses

2x-4

Back to the equation:

+(2x-4)





We calculate terms in parentheses: -((x+3)+(x+5)+(x+4)), so:

(x+3)+(x+5)+(x+4)

We get rid of parentheses

x+x+x+3+5+4

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

2x+2x-3x+8-4-12=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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