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((x+5)(x))/2=75
We move all terms to the left:
((x+5)(x))/2-(75)=0
We multiply all the terms by the denominator
((x+5)x)-75*2=0
We calculate terms in parentheses: +((x+5)x), so:We add all the numbers together, and all the variables
(x+5)x
We multiply parentheses
x^2+5x
Back to the equation:
+(x^2+5x)
(x^2+5x)-150=0
We get rid of parentheses
x^2+5x-150=0
a = 1; b = 5; c = -150;
Δ = b2-4ac
Δ = 52-4·1·(-150)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-25}{2*1}=\frac{-30}{2} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+25}{2*1}=\frac{20}{2} =10 $
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