((x+6)/(x-5))+1=11/x-5

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Solution for ((x+6)/(x-5))+1=11/x-5 equation:


D( x )

x-5 = 0

x = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x = 0

x = 0

x in (-oo:0) U (0:5) U (5:+oo)

(x+6)/(x-5)+1 = 11/x-5 // - 11/x-5

(x+6)/(x-5)-(11/x)+1+5 = 0

(x+6)/(x-5)-11*x^-1+1+5 = 0

(x+6)/(x-5)-11/x+1+5 = 0

(x*(x+6))/(x*(x-5))+(-11*(x-5))/(x*(x-5))+(1*x*(x-5))/(x*(x-5))+(5*x*(x-5))/(x*(x-5)) = 0

x*(x+6)-11*(x-5)+1*x*(x-5)+5*x*(x-5) = 0

x^2+x^2+5*x^2-5*x-5*x-25*x+55 = 0

2*x^2+5*x^2-10*x-25*x+55 = 0

7*x^2-35*x+55 = 0

7*x^2-35*x+55 = 0

7*x^2-35*x+55 = 0

DELTA = (-35)^2-(4*7*55)

DELTA = -315

DELTA < 0

1 = 0

1/(x*(x-5)) = 0

1/(x*(x-5)) = 0 // * x*(x-5)

1 = 0

x belongs to the empty set

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