((x-1)*(x-2))/((x+1)*(x-2))+(-(x+2)*(x+1))/((x+1)*(x-2))-3=0

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Solution for ((x-1)*(x-2))/((x+1)*(x-2))+(-(x+2)*(x+1))/((x+1)*(x-2))-3=0 equation: 



((x-1)(x-2))/((x+1)(x-2))+(-(x+2)(x+1))/((x+1)(x-2))-3=0



Domain of the equation: ((x+1)(x-2))!=0

x∈R



We multiply parentheses ..

((+x^2-2x-1x+2))/((x+1)(x-2))+(-(x+2)(x+1))/((x+1)(x-2))-3=0

We multiply all the terms by the denominator


((+x^2-2x-1x+2))+(-(x+2)(x+1))-3*((x+1)(x-2))=0



We calculate terms in parentheses: +((+x^2-2x-1x+2)), so:

(+x^2-2x-1x+2)

We get rid of parentheses

x^2-2x-1x+2

We add all the numbers together, and all the variables

x^2-3x+2

Back to the equation:

+(x^2-3x+2)





We calculate terms in parentheses: +(-(x+2)(x+1)), so:

-(x+2)(x+1)

We multiply parentheses ..

-(+x^2+x+2x+2)

We get rid of parentheses

-x^2-x-2x-2

We add all the numbers together, and all the variables

-1x^2-3x-2

Back to the equation:

+(-1x^2-3x-2)



We get rid of parentheses

-1x^2+x^2-3x-3x-3*((x+1)(x-2))-2+2=0

We multiply parentheses ..

-1x^2+x^2-3*((+x^2-2x+x-2))-3x-3x-2+2=0

We add all the numbers together, and all the variables

-3*((+x^2-2x+x-2))-6x=0

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