((x-1)/(2x-4))+((x-2)/(3x))=0

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Solution for ((x-1)/(2x-4))+((x-2)/(3x))=0 equation: 


D( x )

3*x = 0

2*x-4 = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

2*x-4 = 0

2*x-4 = 0

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

x in (-oo:0) U (0:2) U (2:+oo)

(x-1)/(2*x-4)+(x-2)/(3*x) = 0

(3*x*(x-1))/(3*x*(2*x-4))+((x-2)*(2*x-4))/(3*x*(2*x-4)) = 0

3*x*(x-1)+(x-2)*(2*x-4) = 0

5*x^2-11*x+8 = 0

5*x^2-11*x+8 = 0

5*x^2-11*x+8 = 0

DELTA = (-11)^2-(4*5*8)

DELTA = -39

DELTA < 0

1 = 0

1/(3*x*(2*x-4)) = 0

1/(3*x*(2*x-4)) = 0 // * 3*x*(2*x-4)

1 = 0

x belongs to the empty set

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