((x-1)/2)+((x-1)/3)+6=x

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Solution for ((x-1)/2)+((x-1)/3)+6=x equation: 



((x-1)/2)+((x-1)/3)+6=x

We move all terms to the left:

((x-1)/2)+((x-1)/3)+6-(x)=0

We add all the numbers together, and all the variables

-1x+((x-1)/2)+((x-1)/3)+6=0

We calculate fractions


-1x+(3x-3)/()+(2x-2)/()+6=0

We multiply all the terms by the denominator


-1x*()+(3x-3)+(2x-2)+6*()=0

We add all the numbers together, and all the variables

-1x*()+(3x-3)+(2x-2)=0

We get rid of parentheses

-1x*()+3x+2x-3-2=0

We add all the numbers together, and all the variables

5x-1x*()-5=0

We move all terms containing x to the left, all other terms to the right

5x-1x*()=5

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