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((x-125)/12)=2x
We move all terms to the left:
((x-125)/12)-(2x)=0
We add all the numbers together, and all the variables
-2x+((x-125)/12)=0
We multiply all the terms by the denominator
-2x*12)+((x-125)=0
Wy multiply elements
-24x^2=0
a = -24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-24)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-48}=0$
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