((x-2)/5)-((x-1)/2)=-4/5

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Solution for ((x-2)/5)-((x-1)/2)=-4/5 equation: 



((x-2)/5)-((x-1)/2)=-4/5

We move all terms to the left:

((x-2)/5)-((x-1)/2)-(-4/5)=0

We get rid of parentheses

((x-2)/5)-((x-1)/2)+4/5=0

We calculate fractions


(2x-4)/()+(-((x-1)*5)*5)/()+()/()=0



We calculate terms in parentheses: +(-((x-1)*5)*5)/(), so:

-((x-1)*5)*5)/(

We multiply all the terms by the denominator


-((x-1)*5)*5)



We calculate terms in parentheses: -((x-1)*5)*5), so:

(x-1)*5)*5

We multiply parentheses

5x+

We add all the numbers together, and all the variables

5x

Back to the equation:

-(5x)



Back to the equation:

+(-5x)



We add all the numbers together, and all the variables

(2x-4)/()+(-5x)+1=0

We get rid of parentheses

(2x-4)/()-5x+1=0

We multiply all the terms by the denominator


(2x-4)-5x*()+1*()=0

We add all the numbers together, and all the variables

(2x-4)-5x*()=0

We get rid of parentheses

2x-5x*()-4=0

We move all terms containing x to the left, all other terms to the right

2x-5x*()=4

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