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D( x )
x+2 = 0
x+2 = 0
x+2 = 0
x+2 = 0 // - 2
x = -2
x in (-oo:-2) U (-2:+oo)
(x-3)/(x+2) = 1 // - 1
(x-3)/(x+2)-1 = 0
(x-3)/(x+2)+(-1*(x+2))/(x+2) = 0
x-1*(x+2)-3 = 0
-5 = 0
-5/(x+2) = 0
-5/(x+2) = 0 // * x+2
-5 = 0
x belongs to the empty set
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