((x-4)+(2x-7))/2=0

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Solution for ((x-4)+(2x-7))/2=0 equation:



((x-4)+(2x-7))/2=0
We multiply all the terms by the denominator
((x-4)+(2x-7))=0
We calculate terms in parentheses: +((x-4)+(2x-7)), so:
(x-4)+(2x-7)
We get rid of parentheses
x+2x-4-7
We add all the numbers together, and all the variables
3x-11
Back to the equation:
+(3x-11)
We get rid of parentheses
3x-11=0
We move all terms containing x to the left, all other terms to the right
3x=11
x=11/3
x=3+2/3

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