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((x-5)+(2x-8))/2=x
We move all terms to the left:
((x-5)+(2x-8))/2-(x)=0
We add all the numbers together, and all the variables
-1x+((x-5)+(2x-8))/2=0
We multiply all the terms by the denominator
-1x*2+((x-5)+(2x-8))=0
We calculate terms in parentheses: +((x-5)+(2x-8)), so:Wy multiply elements
(x-5)+(2x-8)
We get rid of parentheses
x+2x-5-8
We add all the numbers together, and all the variables
3x-13
Back to the equation:
+(3x-13)
-2x+(3x-13)=0
We get rid of parentheses
-2x+3x-13=0
We add all the numbers together, and all the variables
x-13=0
We move all terms containing x to the left, all other terms to the right
x=13
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