((x-5)/(3x))+(6/(2x+1))=0

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Solution for ((x-5)/(3x))+(6/(2x+1))=0 equation: 


D( x )

2*x+1 = 0

3*x = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:-1/2) U (-1/2:0) U (0:+oo)

(x-5)/(3*x)+6/(2*x+1) = 0

((x-5)*(2*x+1))/(3*x*(2*x+1))+(3*6*x)/(3*x*(2*x+1)) = 0

(x-5)*(2*x+1)+3*6*x = 0

2*x^2+9*x-5 = 0

2*x^2+9*x-5 = 0

2*x^2+9*x-5 = 0

DELTA = 9^2-(-5*2*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)-9)/(2*2) or x = (-121^(1/2)-9)/(2*2)

x = 1/2 or x = -5

(x+5)*(x-1/2) = 0

((x+5)*(x-1/2))/(3*x*(2*x+1)) = 0

((x+5)*(x-1/2))/(3*x*(2*x+1)) = 0 // * 3*x*(2*x+1)

(x+5)*(x-1/2) = 0

( x+5 )

x+5 = 0 // - 5

x = -5

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

x in { -5, 1/2 }

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