((x-5)/6)+2=1

Solution for ((x-5)/6)+2=1 equation:

((x-5)/6)+2=1

We move all terms to the left:

((x-5)/6)+2-(1)=0

We add all the numbers together, and all the variables

((x-5)/6)+1=0

We multiply all the terms by the denominator


((x-5)+1*6)=0


We calculate terms in parentheses: +((x-5)+1*6), so:

(x-5)+1*6

We add all the numbers together, and all the variables

(x-5)+6

We get rid of parentheses

x-5+6

We add all the numbers together, and all the variables

x+1

Back to the equation:

+(x+1)


We get rid of parentheses

x+1=0

We move all terms containing x to the left, all other terms to the right

x=-1