((x-6)/2)+((x+2)/4)=32

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Solution for ((x-6)/2)+((x+2)/4)=32 equation: 



((x-6)/2)+((x+2)/4)=32

We move all terms to the left:

((x-6)/2)+((x+2)/4)-(32)=0

We calculate fractions


(4x-24)/()+(2x+4)/()-32=0

We multiply all the terms by the denominator


(4x-24)+(2x+4)-32*()=0

We add all the numbers together, and all the variables

(4x-24)+(2x+4)=0

We get rid of parentheses

4x+2x-24+4=0

We add all the numbers together, and all the variables

6x-20=0

We move all terms containing x to the left, all other terms to the right

6x=20

x=20/6

x=3+1/3

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