((x-7)/3)-((6x-2)/4)=4

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Solution for ((x-7)/3)-((6x-2)/4)=4 equation: 



((x-7)/3)-((6x-2)/4)=4

We move all terms to the left:

((x-7)/3)-((6x-2)/4)-(4)=0

We calculate fractions


(4x-28)/()+(-18x+6)/()-4=0

We multiply all the terms by the denominator


(4x-28)+(-18x+6)-4*()=0

We add all the numbers together, and all the variables

(4x-28)+(-18x+6)=0

We get rid of parentheses

4x-18x-28+6=0

We add all the numbers together, and all the variables

-14x-22=0

We move all terms containing x to the left, all other terms to the right

-14x=22

x=22/-14

x=-1+4/7

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