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((x/2)+2x)=x+3
We move all terms to the left:
((x/2)+2x)-(x+3)=0
Domain of the equation: 2)+2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
((+x/2)+2x)-(x+3)=0
We get rid of parentheses
((+x/2)+2x)-x-3=0
We multiply all the terms by the denominator
((+x-x*2)+2x)-3*2)+2x)=0
We calculate terms in parentheses: +((+x-x*2)+2x), so:Wy multiply elements
(+x-x*2)+2x
We add all the numbers together, and all the variables
2x+(+x-x*2)
We get rid of parentheses
2x+x-x*2
We add all the numbers together, and all the variables
3x-x*2
Wy multiply elements
3x-2x
We add all the numbers together, and all the variables
x
Back to the equation:
+(x)
x-6x=0
We add all the numbers together, and all the variables
-5x=0
x=0/-5
x=0
Równanie nie ma rozwiązania
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