((x/25)-(1/x))/1+(5/x)

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Solution for ((x/25)-(1/x))/1+(5/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x/25-(1/x))/1+5/x = 0

x/25-x^-1+5/x = 0

1/25*x^1+4*x^-1 = 0

(1/25*x^2+4*x^0)/(x^1) = 0 // * x^2

x^1*(1/25*x^2+4*x^0) = 0

x^1

(1/25)*x^2+4 = 0

(1/25)*x^2+4 = 0

DELTA = 0^2-(4*4*(1/25))

DELTA = -16/25

DELTA < 0

x in { } 

x belongs to the empty set

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