((x/9)-(1/x))/((7/9)-(7/3x))

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Solution for ((x/9)-(1/x))/((7/9)-(7/3x)) equation:


D( x )

x = 0

7/9-((7/3)*x) = 0

x = 0

x = 0

7/9-((7/3)*x) = 0

7/9-((7/3)*x) = 0

(-7/3)*x+7/9 = 0

7/9-7/3*x = 0 // - 7/9

-7/3*x = -7/9 // : -7/3

x = -7/9/(-7/3)

x = 1/3

x in (-oo:0) U (0:1/3) U (1/3:+oo)

(x/9-(1/x))/(7/9-((7/3)*x)) = 0

(x/9-x^-1)/((-7/3)*x+7/9) = 0

(1/9*x-x^-1)/(7/9-7/3*x) = 0

1/9*x-x^-1 = 0

x^-1*(1/9*x^2-1) = 0

1/9*x^2 = 1 // : 1/9

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x^-1*(x-3)*(x+3) = 0

(x^-1*(x-3)*(x+3))/(7/9-7/3*x) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-3 )

x-3 = 0 // + 3

x = 3

( x^-1 )

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x in { -3, 3 }

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