((y-5)/(y-6))-1=((y-3)/(y-7))

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Solution for ((y-5)/(y-6))-1=((y-3)/(y-7)) equation:


D( y )

y-7 = 0

y-6 = 0

y-7 = 0

y-7 = 0

y-7 = 0 // + 7

y = 7

y-6 = 0

y-6 = 0

y-6 = 0 // + 6

y = 6

y in (-oo:6) U (6:7) U (7:+oo)

(y-5)/(y-6)-1 = (y-3)/(y-7) // - (y-3)/(y-7)

(y-5)/(y-6)-((y-3)/(y-7))-1 = 0

(y-5)/(y-6)+(-1*(y-3))/(y-7)-1 = 0

((y-5)*(y-7))/((y-6)*(y-7))+(-1*(y-3)*(y-6))/((y-6)*(y-7))+(-1*(y-6)*(y-7))/((y-6)*(y-7)) = 0

(y-5)*(y-7)-1*(y-3)*(y-6)-1*(y-6)*(y-7) = 0

13*y-y^2-3*y-42+17 = 0

10*y-y^2-25 = 0

10*y-y^2-25 = 0

10*y-y^2-25 = 0

DELTA = 10^2-(-25*(-1)*4)

DELTA = 0

y = -10/(-1*2)

y = 5 or y = 5

(y-5)^2 = 0

((y-5)^2)/((y-6)*(y-7)) = 0

((y-5)^2)/((y-6)*(y-7)) = 0 // * (y-6)*(y-7)

(y-5)^2 = 0

y-5 = 0 // + 5

y = 5

y in { 5, 5 }

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