((z+6)/3)=((2z)/4)

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Solution for ((z+6)/3)=((2z)/4) equation: 



((z+6)/3)=((2z)/4)

We move all terms to the left:

((z+6)/3)-(((2z)/4))=0

We add all the numbers together, and all the variables

((z+6)/3)-((+2z/4))=0

We calculate fractions


z/()+(-((+2z*3))/()=0



We calculate terms in parentheses: +(-((+2z*3))/(), so:

-((+2z*3))/(

We multiply all the terms by the denominator


-((+2z*3))



We calculate terms in parentheses: -((+2z*3)), so:

(+2z*3)

We get rid of parentheses

2z*3

Wy multiply elements

6z

Back to the equation:

-(6z)



Back to the equation:

+(-6z)



We get rid of parentheses

z/()-6z=0

We multiply all the terms by the denominator


z-6z*()=0

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