(-(3/2)y)=-12

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Solution for (-(3/2)y)=-12 equation: 



(-(3/2)y)=-12

We move all terms to the left:

(-(3/2)y)-(-12)=0



Domain of the equation: 2)y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(-(+3/2)y)-(-12)=0

We add all the numbers together, and all the variables

(-(+3/2)y)+12=0

We multiply all the terms by the denominator


(-(+3+12*2)y)=0



We calculate terms in parentheses: +(-(+3+12*2)y), so:

-(+3+12*2)y

We add all the numbers together, and all the variables

-27y

Back to the equation:

+(-27y)



We get rid of parentheses

-27y=0

y=0/-27

y=0

Równanie nie ma rozwiązania

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