(-(n/3))=3

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Solution for (-(n/3))=3 equation: 



(-(n/3))=3

We move all terms to the left:

(-(n/3))-(3)=0

We add all the numbers together, and all the variables

(-(+n/3))-3=0

We multiply all the terms by the denominator


(-(+n-3*3))=0



We calculate terms in parentheses: +(-(+n-3*3)), so:

-(+n-3*3)

We add all the numbers together, and all the variables

-(n-9)

We get rid of parentheses

-n+9

We add all the numbers together, and all the variables

-1n+9

Back to the equation:

+(-1n+9)



We get rid of parentheses

-1n+9=0

We move all terms containing n to the left, all other terms to the right

-n=-9

n=-9/-1

n=+9

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