(-1(2-x))/2=(3x-5)/3

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Solution for (-1(2-x))/2=(3x-5)/3 equation: 



(-1(2-x))/2=(3x-5)/3

We move all terms to the left:

(-1(2-x))/2-((3x-5)/3)=0

We add all the numbers together, and all the variables

(-1(-1x+2))/2-((3x-5)/3)=0

We calculate fractions


3x/()+(-((3x-5)*2)/()=0



We calculate terms in parentheses: +(-((3x-5)*2)/(), so:

-((3x-5)*2)/(

We multiply all the terms by the denominator


-((3x-5)*2)



We calculate terms in parentheses: -((3x-5)*2), so:

(3x-5)*2

We multiply parentheses

6x-10

Back to the equation:

-(6x-10)



We get rid of parentheses

-6x+10

Back to the equation:

+(-6x+10)



We get rid of parentheses

3x/()-6x+10=0

We multiply all the terms by the denominator


3x-6x*()+10*()=0

We add all the numbers together, and all the variables

3x-6x*()=0

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