(-1+-2x)(3+-8x)=0

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Solution for (-1+-2x)(3+-8x)=0 equation: 



(-1+-2x)(3+-8x)=0

We add all the numbers together, and all the variables

(-2x)(-8x)=0

We multiply parentheses ..

(+16x^2)=0

We get rid of parentheses

16x^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$

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