(-1+1/2)h=4

Solution for (-1+1/2)h=4 equation:

(-1+1/2)h=4

We move all terms to the left:

(-1+1/2)h-(4)=0


Domain of the equation: 2)h!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

(1/2-1)h-4=0

We multiply parentheses

h^2-1h-4=0

a = 1; b = -1; c = -4;
Δ = b2-4ac
Δ = -12-4·1·(-4)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{17}}{2*1}=\frac{1-\sqrt{17}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{17}}{2*1}=\frac{1+\sqrt{17}}{2}
$