(-1+i)(-1+i)+2(-1+i)+2=0

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Solution for (-1+i)(-1+i)+2(-1+i)+2=0 equation: 



(-1+i)(-1+i)+2(-1+i)+2=0

We add all the numbers together, and all the variables

(i-1)(i-1)+2(i-1)+2=0

We multiply parentheses

(i-1)(i-1)+2i-2+2=0

We multiply parentheses ..

(+i^2-1i-1i+1)+2i-2+2=0

We add all the numbers together, and all the variables

(+i^2-1i-1i+1)+2i=0

We get rid of parentheses

i^2-1i-1i+2i+1=0

We add all the numbers together, and all the variables

i^2+1=0

a = 1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·1·1
Δ = -4
Delta is less than zero, so there is no solution for the equation

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