(-1-7i)(-8+6i)=0

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Solution for (-1-7i)(-8+6i)=0 equation:



(-1-7i)(-8+6i)=0
We add all the numbers together, and all the variables
(-7i-1)(6i-8)=0
We multiply parentheses ..
(-42i^2+56i-6i+8)=0
We get rid of parentheses
-42i^2+56i-6i+8=0
We add all the numbers together, and all the variables
-42i^2+50i+8=0
a = -42; b = 50; c = +8;
Δ = b2-4ac
Δ = 502-4·(-42)·8
Δ = 3844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3844}=62$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-62}{2*-42}=\frac{-112}{-84} =1+1/3 $
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+62}{2*-42}=\frac{12}{-84} =-1/7 $

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